neptune 开发板 w800 的 UART1 可以用 tls_uart_write 发送数据, 但是怎么用 tls_uart_read 获取串口发送过来的数据?
case DEMO_MSG_UART_RECEIVE_DATA:
{
rx_len = uart-" rx_data_len;
while (rx_len " 0)
{
printf ("\n----1 rx_len----%d", rx_len) ;
len = (rx_len " DEMO_UART_RX_BUF_SIZE) ? DEMO_UART_RX_BUF_SIZE : rx_len;
printf ("\n----2 len----%d", len) ;
memset (uart-" rx_buf, 0, (DEMO_UART_RX_BUF_SIZE + 1) ) ;
tls_uart_read (TLS_UART_1, msg_rxfifo_buf, len) ;
tls_uart_read (TLS_UART_1, rx_fifo_buf1[0], len) ;
printf ("\n----#### msg_rxfifo_buf----%s\n", msg_rxfifo_buf) ;
printf ("\n----#### rx_fifo_buf1[0]----%s\n", rx_fifo_buf1[0]) ;
ret = tls_uart_read (TLS_UART_1, (u8 *) uart-" rx_buf, len) ;
ret = tls_uart_read (TLS_UART_1, (u8 *) uart-" rx_buf, len) ; /* input */
printf ("\n----#### DEMO_MSG_UART_RECEIVE_DATA----%s\n", uart-" rx_buf) ;
printf ("\n----3 ret----%d", ret) ;
if (ret "= 0)
{
break;
}
rx_len -= ret;
uart-" rx_data_len -= ret;
if USE_DMA_TX_FTR
// tls_uart_dma_write (uart-" rx_buf, len, uart_dma_done, TLS_UART_1) ;
else
tls_uart_write (TLS_UART_1, uart-" rx_buf, len) ; /* output */
printf ("\n----4 DEMO_MSG_UART_RECEIVE_DATA uart-" rx_buf----%s\n", uart-" rx_buf) ;
endif
}
printf ("\n----5 DEMO_MSG_UART_RECEIVE_DATA uart-" rx_msg_num----%s\n", uart-" rx_msg_num) ;
if (uart-" rx_msg_num " 0)
{
uart-" rx_msg_num--;
}
printf ("\n----6 DEMO_MSG_UART_RECEIVE_DATA----%s\n", uart-" rx_buf) ;
}
break;
代码用的是开发板自带的 wm_uart_demo. c
我修改了下, 运行得不到发送过来的 1234
case DEMO_MSG_UART_RECEIVE_DATA:
{
rx_len = uart-" rx_data_len;
while (rx_len " 0)
{
printf ("\n----1 rx_len----%d", rx_len) ;
len = (rx_len " DEMO_UART_RX_BUF_SIZE) ? DEMO_UART_RX_BUF_SIZE : rx_len;
printf ("\n----2 len----%d", len) ;
memset (uart-" rx_buf, 0, (DEMO_UART_RX_BUF_SIZE + 1) ) ;
tls_uart_read (TLS_UART_1, msg_rxfifo_buf, len) ;
tls_uart_read (TLS_UART_1, rx_fifo_buf1[0], len) ;
printf ("\n----#### msg_rxfifo_buf----%s\n", msg_rxfifo_buf) ;
printf ("\n----#### rx_fifo_buf1[0]----%s\n", rx_fifo_buf1[0]) ;
ret = tls_uart_read (TLS_UART_1, (u8 *) uart-" rx_buf, len) ;
ret = tls_uart_read (TLS_UART_1, (u8 *) uart-" rx_buf, len) ; /* input */
printf ("\n----#### DEMO_MSG_UART_RECEIVE_DATA----%s\n", uart-" rx_buf) ;
printf ("\n----3 ret----%d", ret) ;
if (ret "= 0)
{
break;
}
rx_len -= ret;
uart-" rx_data_len -= ret;
// tls_uart_dma_write (uart-" rx_buf, len, uart_dma_done, TLS_UART_1) ;
tls_uart_write (TLS_UART_1, uart-" rx_buf, len) ; /* output */
printf ("\n----4 DEMO_MSG_UART_RECEIVE_DATA uart-" rx_buf----%s\n", uart-" rx_buf) ;
}
printf ("\n----5 DEMO_MSG_UART_RECEIVE_DATA uart-" rx_msg_num----%s\n", uart-" rx_msg_num) ;
if (uart-" rx_msg_num " 0)
{
uart-" rx_msg_num--;
}
printf ("\n----6 DEMO_MSG_UART_RECEIVE_DATA----%s\n", uart-" rx_buf) ;
}
break;
代码用的是开发板自带的 wm_uart_demo. c
我修改了下, 运行得不到发送过来的 1234
就是获取不到, 请看下我的代码有什么问题
建议你先把 demo 跑成功了, 再去修改, 另外 tls_uart_read 后面的长度 已经写了 len 之后, 只需要调用一次就行了 , 还有 tls_uart_read (TLS_UART_1, rx_fifo_buf1[0], len) ; 本身就是错误的用法
源代码是这样的:
case DEMO_MSG_UART_RECEIVE_DATA: